3x^2+61x=180

Solution for 3x^2+61x=180 equation:

3x^2+61x=180

We move all terms to the left:

3x^2+61x-(180)=0

a = 3; b = 61; c = -180;
Δ = b2-4ac
Δ = 612-4·3·(-180)
Δ = 5881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{5881}}{2*3}=\frac{-61-\sqrt{5881}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{5881}}{2*3}=\frac{-61+\sqrt{5881}}{6}
$